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3 years ago

13

Solve for X. I can't seem to figure out how to isolate the X. The answers of course are X = 0,2 but I need to know the process.

Thank you! $2^x = \frac{3}{2}x + 1$

1 answer:

marin [14]3 years ago

7 0

There is no algebraic way of isolating X unfortunately.
For these equations, you have to solve with numerical approximation.
I suggest Newtons method if you know calculus.

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WILL MARK BRAINLIEST!!!!!! 25 PTS

LuckyWell [14K]

Answer:

no

Step-by-step explanation:

SAS stands for side angle side. so in this question we know that one side is equal to another side, but we don't know wether or not there is another angle and another side that is congruent. so for that reason it is not congruent by SAS.

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3 years ago

Solve the absolute value equation. If no solution write NO SOLUTION.<br> -{2x + 3] + 8<br> 12

Natasha2012 [34]

Answer:

If problem is "-|2x+3|+8=12"

then there is (<em>no solution.)</em>

Step-by-step explanation:

Let's solve your equation step-by-step.

−|2x+3|+8=12

Step 1: Add -8 to both sides.

−|2x+3|+8+−8=12+−8

−|2x+3|=4

Step 2: Divide both sides by -1.

−|2x+3|=4

-1 -1

|2x+3|=−4

Step 3: Solve Absolute Value.

|2x+3|=−4

No solutions Because absolute value is less than 0.

4 0

3 years ago

What are the partial quotations of 378 and 145

kramer

If it is adding it is going to be 623

7 0

3 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$

$(25+1)^2=(25-1)^2+(10)^2$

$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

Let (x,y)=(5,2).

$(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2$

$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

$(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2$

$(25+9)^2=(25-9)^2+(30)^2$

$(34)^2=(16)^2+(30)^2$

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

$(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2$

$(25+16)^2=(25-16)^2+(40)^2$

$(41)^2=(9)^2+(40)^2$

Another is (9,40,41).

5 0

3 years ago

Find the four geometric means between 486 and 2

melamori03 [73]

Answer:

486, 486r,486r^2,486r^3,486r^4,2

------------------------------------

2 = 486r^5

-----

r^5= 1/243

----

r = 1/3

---

------

Ans: 486*(1/3),486*(1/9),486(1/27),486(1/81)

-----

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers