A square of area 121 ft² will have a side dimension of √121 ft = 11 ft. The perimeter is the length of 4 sides, so is 44 ft.
I’m not really sure but I would say c
Answer:
Step-by-step explanation:
We are given that linear differential equation
Auxillary equation
C.F=
P.I=
P.I=
P.I=
and 
where D square is replace by - a square
P.I=
Hence, the general solution
G.S=C.F+P.I
Answer: 1/6
Step-by-step explanation: ok, so he had mowed 1/3 of a field in 2 hours. Take 1/3 and divide by 2 hours to get 1/6
Answer:
The correct options are;
D. Triangles ABC and A'B'C' are congruent
E. Angle ABC is congruent to angle A'B'C'
F. Segment BC is congruent to segment B'C'
H. Segment AQ is congruent to segment A'Q'
Step-by-step explanation:
The given information are;
The angle of rotation of triangle ABC = 60°
Therefore, given that a rotation of a geometric figure about a point on the coordinate plane is a form of rigid transformation, we have;
1) The length of the sides of the figure of the preimage and the image are congruent
Therefore;
BC ≅ B'C'
2) The angles formed by the sides of the preimage are congruent to the angles formed by the corresponding sides of the image
Therefore;
∠ABC ≅ ∠A'B'C'
3) The distances of the points on the figure of the preimage from the coordinates of the point of rotation are equal to the distances of the points on the figure of the image from the coordinates of the point of rotation
Therefore;
Segment AQ ≅ A'Q'.
