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muminat
3 years ago
6

Valor de x de (5x-20) 85

Mathematics
1 answer:
aleksandrvk [35]3 years ago
4 0
Answer/valor de x is x=21
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Find the constant of variation k for the direct variation
MAVERICK [17]
F(x) = a.x . We ha to calculate a.

Back to the table, let's rewrite the coordinates

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8 0
3 years ago
tina baked 955 cookies for a big super bowl party she had to put the cookies on 8 different tables in the party room if she spit
sveta [45]

Answer:

119 cookies on each plate and 3 cookies leftover

Step-by-step explanation:

Cookies on each plate:

955 divided by 8 is 119.375 but round it to 119.

Cookies leftover:

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8 0
3 years ago
A marching band wants to line up for their performance. When they line up in threes there are 2 left over. When they line up in
Naya [18.7K]

Answer: They are 59 members in the band

Step-by-step explanation:

given data:

when lined up in 3 = 2 left.

when lined up in 4 = 3 left

when they are lined up in 5 = 4 left

when they are lined up in 6 = 5 left

Solution:

From the given data, we know the band number ends with 9, so we start with 9,29,49,59. We test till we arrive at our desired answer.

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59/4 = 14 R 3.

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They are 59 members in the band.

6 0
3 years ago
What is the equivalent fraction for 4\7
Bingel [31]
4/7 = 8/14 = 12/21 = 16/28, etc
7 0
3 years ago
Read 2 more answers
Helppppp meeeeeeeeeeeeeeeeee
kati45 [8]

Answer:

The length of the shortest piece is 1\textrm{ ft}.

The length of the medium-sized piece is 3\textrm{ ft}.

The length of the longest piece is 7\textrm{ ft}.

Step-by-step explanation:

The five-step method is GUESS method.

Given:

Length of copper wire, L=11\textrm{ ft}

Length of longest piece is 6 feet longer than the shortest one.

Length of the medium-sized piece is 3 times the shortest one.

Unknown:

Length of longest, medium-sized and shortest pieces of wire.

Let the length of shortest piece be x feet.

Therefore, the length of longest piece is equal to 6+x.

And, length of the medium-sized piece is equal to 3x.

Evaluate:

Sum of lengths of longest, medium-sized and shortest pieces of wire is equal to the total length of wire. So,

6+x+x+3x=11\\5x+6=11\\5x=11-6\\5x=5\\x=\frac{5}{5}=1

Substitute and Solve:

Now, we have, x=1.

Substitute 1 for x and solve for each sizes of wire pieces. This gives,

Length of shortest piece = x=1\textrm{ ft}

Length of medium-sized piece = 3x=3(1)=3\textrm{ ft}

Length of longest piece = 6+x=6+1=7\textrm{ ft}

Therefore, the lengths of shortest, medium-sized, and longest pieces are 1\textrm{ ft}, 3\textrm{ ft} and 7\textrm{ ft} respectively.

5 0
3 years ago
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