Answer:
Step-by-step explanation:
Answer:
u are fricked my dude
Step-by-step explanation:
Answer:
2<-1
Step-by-step explanation:
7s-9<6s-10
-6s. -6s.
S-9<-10
+9. +9
S<-1
Answer:
(a) What is the probability that a randomly chosen 10 year old is shorter than 51 inches?
Formula :
refer the z table
P(z<-0.66)=0.2546
Hence the probability that a randomly chosen 10 year old is shorter than 51 inches is 0.2546
(b) What is the probability that a randomly chosen 10 year old is between 57 and 67 inches?
Formula :
refer the z table
P(z<0.333)=0.6293
refer the z table
P(z<2)=0.9772
P(57<x<67)=P(0.333<z<2)=P(z<2)-P(z<0.333)= 0.9772-0.6293=0.3479
Hence the probability that a randomly chosen 10 year old is between 57 and 67 inches is 0.3479
c) If the tallest 10% of the class is considered "very tall", what is the height cutoff for "very tall"?
1 - 0.10 = 0.9
Refer the z table
probability of shortest = 0.98
z corresponding 0.9 = 1.28
Hence the height cutoff for "very tall" is 62.98
d)The height requirement for Batman the Ride at Six Flags Magic Mountain is 54 inches. What percent of 10 year olds cannot go on this ride?
p(z<-0.166)=0.4364
Hence 43.64% of 10 year olds cannot go on this ride
Answer:
Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips are white. Then,
a) Find α
α = P (reject H0 | H0 is true) = P (X ≥ 2|E)
= P (X = 2|E) + P (X = 3|E),
We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution
= (5C2 * 5C1)/10C3 + (5C3 * 5C0)/10C3
= 0.5
So, α = 0.5
b) Find β
i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)
β = P (accept H0 | E1) = P (X ≤ 1|E1)
= (6C0 * 4C3)/10C3 + (6C1 * 4C2)/10C3
= 1/3
= 0.333
So, β = 0.333
i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)
β = P (accept H0 | E2) = P (X ≤ 1|E2)
= (7C0 * 3C3)/10C3 + (7C1 * 3C2)/10C3
= 11/60
= 0.183
So, β = 0.183