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2 years ago

The cost of 1 purse and 1 watch is £27.

1 answer:

4 0

1 purse and 1 watch is 27€
2 purse and 1 watch is 41€

So we can see the watch is constant means 1 watch is every time but purse is increase by 1 in the next expression

So 41-27 = 14€ is one purse
because the watch is every time one, so the next value increase is by purse

1purse and 1watch = 27
We know,
1 purse is 14€
So 27-14=13€ is one watch

We can check by
1 purse is 14 so two purse is 14*2=28
28+13=41
Which is same as they said in second expression

Hope it help you!¡

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My car gets 23 miles per gallon at 60 miles per hour. Is the number of miles I can drive at 60 miles per hour a linear function

stiv31 [10]

9514 1404 393

Answer:

yes

Step-by-step explanation:

The constant ratio (23 mi)/(1 gal) tells you the number of miles is a linear function of the number of gallons.

miles = (miles/gallon) × gallons

miles = constant × gallons . . . . . a linear function of gallons

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2 years ago

How many terms are in the expression shown? 2n + 5 – 3p + 4q 1 2 3 4

MA_775_DIABLO [31]

Step-by-step explanation: A term can be a number, a variable, or a number times one or more variables.

So in this expression, the terms are +2n, +5, -3p, and +4q.

This means that there are 4 terms.

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3 years ago

Read 2 more answers

Find the terms, coefficients, and constants of 4x+x+17

andreyandreev [35.5K]

Answer:

17 and x=constant,

4x=coefficient

hope this helps

have a good day :)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Mrs galvan's truck averages 24.94 miles per gallon of gasoline. His gasoline tank holds a maximum of 25 gallons. How far could M

ch4aika [34]

Answer: He could drive 623.5 miles on a full tank of gasoline

Step-by-step explanation:

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3 years ago

The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

5 0

2 years ago