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2 years ago

2.5x) 10-8) (9•10^-10)

Mathematics

1 answer:

evablogger [386]2 years ago

5 0

Answer:

Patanahi bhhai sorry bro plz

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Use the rectangle hexagon with side length 10 meters to fill in the missing information

Vlada [557]

Answer:

$A_h=150\sqrt{3}\ m^2$

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

$x=5 m$

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

$\theta=360/12=30^o$

Now we have $\theta$ , the height of the triangle y is easily found by

$\displaystyle tan30^o=\frac{x}{y}$

Solving for y

$\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}$

The value of z can be found by using

$\displaystyle sin30^o=\frac{x}{z}$

$\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10$

The area of the triangle is

$\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}$

The area of the hexagon is 12 times the area of the triangle, thus

$\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}$

$\boxed{A_h=150\sqrt{3}\ m^2}$

6 0

3 years ago

Answer to 10 plzzzzzzzzzzzzzzzzzzzzzzzzzzzz

evablogger [386]

Answer:

B. 2/3

Step-by-step explanation:

0 is less than 1 but not greater than 0.

1 isn't less than 1 but is greater than 0.

3/2 is actually 1.5. 1.5 isn't less than 1 but is greater than 0.

The correct answer is 2/3 because:

2/3 is less than 1 whole.

2/3 is greater than 0.

Hope this helps.

8 0

3 years ago

The population of Medfield is 7000. Capital City's population is 8/25ths of Medfield's. What is Capital City's population?

mixas84 [53]

Hi friend,
Capital City's population would be B) 2240

6 0

2 years ago

Read 2 more answers

The diagram above shows a circle with centre O and radius 25 cm.

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Notice that KL = LM and PQ = QR since OL and OQ are perpendicular to both KM and PR.

It follows that QR = (1/2) PR = 20 cm. We also know that MR = 21.

Now in order to solve the problem we just need OQ=OL

$OQ^2=OR^2-QR^2= 25^2-20^2 =225\\OQ=15$

Therefore the perimeter of the pentagon is

$OL+LM+MR+RQ+Q)\\= 15+20+21+20+15= 91$

8 0

2 years ago

The length of a rectangle is 5cm greater than its width. The perimeter is 58. What are the dimensions of the rectangle

Doss [256]

Perimeter= 2w+2l
l=w+5

Substitute for l
p= 2w+2(w+5)
p= 2w+2w+10
p= 4w+10
58=4w+10
48=4w
12= w

Plug in the width to find length.
l= 12+5
l=17

Final answer: Length-17 cm, Width-12 cm

7 0

3 years ago

Read 2 more answers