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kifflom [539]
3 years ago
7

Learning ObjectivesIn this activity, you'll practice determining the limiting reagent for a reaction between silver nitrate and

copper metal. In part 1 you'll make the measurements you need so you can predict the amount of silver produced. In part 2 you'll be able to measure how much silver was actually produced. Finally you will be asked to consider possible reasons for the discrepancy.Part 1: Describe the ReactionIn this activity, you will be observing a reaction where copper and silver nitrate react to form copper (II) nitrate and silver.1.Write a balanced chemical equation for this reaction.2AgNO3 Cu -> 2Ag Cu(NO3)2Score: 0 / 12.
Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer:

Explanation:

The balanced chemical reaction equation is;

2AgNO3(aq) + Cu(s) -> 2Ag(s) + Cu(NO3)2(aq)

When we balance chemical reaction equations, we ensure that the number of atoms of each element on the left hand side of the reaction equation is exactly the same number of atoms of each element on the right hand side of the reaction equation.

Let us consider this reaction;

There are two atoms of Ag on both sides of the reaction equation

There are six atoms of O on both sides of the reaction equation

There are 2 atoms of N on both sides of the reaction equation

There is one atom of Cu on both sides of the reaction equation.

Hence, the reaction equation is balanced.

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Both types of waves transfer energy

Explanation:

I think that's right

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What two forces act in the nucleus to create a 'nuclear tug-of-war'?
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Answer:

Electrostatic repulsion, strong nuclear force

Explanation:

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3 years ago
The volume of a sphere is given by the equation =4/33, where is the radius. Calculate the volume of a sphere with a radius of 34
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3 years ago
A serving of Cheez-Its releases 1.30 x 10^4 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy we
kondor19780726 [428]

Answer:

The final temperature is:- 7428571463.57 °C

Explanation:

The expression for the calculation of heat is shown below as:-

Q=m\times C\times \Delta T

Where,  

Q  is the heat absorbed/released

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)

Specific heat of water = 4.18 J/g°C

Initial temperature = 35 °C

Final temperature = x °C

\Delta T=(x-35)\ ^0C/tex]
Q = [tex]1.3\times 10^4 kcal

Also, 1 kcal = 4.18 kJ = 4.18\times 10^3 J

So, Q = 1.3\times 10^4\times 4.18\times 10^3 J = 54340000 J

So,  

54340000=0.00175\times 4.18\times (x-35)

0.00175\times \:4.18\left(x-35\right)=54340000

x-35=\frac{54340000}{0.007315}

x=7428571463.57

Thus, the final temperature is:- 7428571463.57 °C

3 0
3 years ago
Heyy pls help anyone?
madam [21]
1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

i’m not sure about the rest but i hope this helped ^^
7 0
3 years ago
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