Answer:
164
Step-by-step explanation:
A= 2(wh+lw+lh)
just plug it in and you'll get your answers for surface area
Answer:
Y=-4x+8
Step-by-step explanation:
Answer:
Solution given:
Y=90°
∠X=73°.
∠ZWY=80°
and XW=80.
ZY=?
We know that
In right angled triangle ∆ XYZ
Tan 73=
3.27=
3.27×[xy]=yz
xw+wy=
wy=
-80...........(1)
again
In right angled triangle WYZ
Tan 80=
5.67×wy=yz
wy=
yz=5.67×wy............................................(2)
E<u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u>&</u><u>2</u>
=
-80
-
=80
5.67yz-3.27yz=80*5.67*3.27
2.4yz =1483.272
yz=
yz=618.03
:.y=618.03unit.<u>the length of ZY to the nearest 100</u><u>th</u><u> </u><u>is</u><u> </u><u>6</u><u>1</u><u>8</u><u>.</u>
1 1/8 square feet
1 4/5 • 1 5/8 = 9/8
9/8 reduces to 1 1/8
I hope this helps you :)
Answer:
min = a_1
for i:= 2 to n:
if
< min then min = 
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if
< min then min = 
return min