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3 years ago

What is 5 (z+4) +5 (2-z) simplified?

Mathematics

1 answer:

Sholpan [36]3 years ago

7 0

Answer:

Step-by-step explanation:

Multiply: 5z+20+10-5z

Simplify: Both z's cancel and you get 30

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Help me please thanks

kow [346]

Correct answer:
First reflect across the y-axis, then rotate 90 degrees clockwise about point K, then shift 3 units down.

6 0

3 years ago

Find the value of the variables. Diagram above. Tysm please help very urgent!

serious [3.7K]

Answer:

If you look at the different triangles in the star they give you two angles....

all of the points in a triangle would be equal and you just subtract 24 from 105

x is 24 and y is 81

Step-by-step explanation:

8 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

The function f(x) = 6x + 5 is one-to-one. Find an equation for f '(x), the inverse function.

Hatshy [7]

Switch the x and y values and isolate y, then simplify.
x=6y+5
6y=x-5
y=1/6x-5/6

4 0

3 years ago

Giving 15 points for help!

kolezko [41]

Answer: The correct statements are 'The equation 2n = p should be 2p = n' , 'The actual cost of the onions is $3.00 per pound' and 'Potatoes cost $1.50 per pound.'

Step-by-step explanation:

Here, p represents cost of one potato and n represents the cost of one onion.

And, According to the question, He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18.

Therefore, 6p +3n = 18 ------(1)

And, Onions cost twice as much as potatoes.

Therefore, n= 2p ---------(2)

Putting the values of n from 2) in equation 1),

we get, 6p+3(2p)=18

⇒6p+6p=18 ⇒ 12p =18 ⇒ p = 1.5 dollar.

Thus cost of one potato= $1.5

And cost of one onion = $ 2× 1.5= $ 3.00

Thus with help of above explanation we can say that Options first, third and fifth are correct.

8 0

4 years ago

Read 2 more answers