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Mademuasel [1]
3 years ago
13

Pls give me the correct answer

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

-21, -16, -14, -12, -11.

and

p≤−11

Hope this helps!

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Suppose task B follows task A. The likelihood that a problem will occur with task A is 0.5, and the time to correct the problem
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Answer:

The risk consequence of both activities is 1.6 months.

Step-by-step explanation:

We can define a randome variable D: total delay time for the project, and calculate its expected value.

This would be the risk consequence of both activities.

The expected delay time for the project is the sum of the expected delay for task A plus the expected delay for task B. It is assumed the likelihood of a problem in any task is independent of the other.

Then, each expected delay for a task is equal to the probability of a problem multiplied by the consequence (delay time).

E(D)=E(D_a)+E(D_b)=p_aT_a+p_bT_b\\\\E(D)=0.5*2+0.2*3=1+0.6=1.6

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3 years ago
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VashaNatasha [74]

Subtract 7 from both sides

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Simplify 12 - 7 to 5

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<u>n > 5</u>

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