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3 years ago

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A line passes through (2,−7) and (−3,3) . find the slope-intercept form of the equation of the line. then fill in the value of t

he slope, m, and the value of the y-intercept, b, below

1 answer:

ad-work [718]3 years ago

8 0

Slope/m=3-(-7)/-3-2=10/-5=-2
slope/m=-2
y=-2x+b
b= 3=-2*-3+b
b=-3

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Answer:

Let the cost of each popcorn bag be x and cost of each drink be y

Cost of 9 bags of Popcorn= 9 x

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According to Question

9 x + 8 y= 49..................... equation (1)

Similarly , cost of 3 popcorn = 3 x

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According to Question

3 x+ 3 y= $ 17.25...................equation(2)

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9 x + 9 y = 51.75..................equation(3)

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put value of y in any equation (2)

we get

3 x + 3 × 2.75 = 17.25

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Answer:

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A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

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✰ <u>Concept</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ <u>Given</u><u> </u><u>Information</u><u> </u>:-

⠀

Hypotenuse = 22 ft.
Base = 10 ft.

⠀

✰ <u>To Find</u><u> </u><u>:</u><u>-</u>

⠀

The value of side or the perpendicular

⠀

✰ <u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

⠀

✰ <u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$

Thus, option B. 19.60 ft. is the correct option.

⠀

$\underline{\rule{230pt}{2pt}} \\ \\$

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