3 years ago

A) n(n + 2) 224b)x² + x = 156

1 answer:

8 0

Step-by-step explanation:

${x}^{2} + x - 156 = 0 \\ (x + 13)(x - 12) = 0 \\ x = - 13 \\ or \\ x = 12$

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Natali [406]

Answer:

6/7 ≈ 85.7%

Step-by-step explanation:

The probability that a 0 was transmitted and received is 0.5·0.9 = 0.45.

The probability that a 1 was transmitted and a 0 received is 0.5·0.15 = 0.075.

Then the probability that a 0 was received is 0.45 +0.075 = 0.525.

The probability of interest is ...

p(0 transmitted | 0 received) = p(0 transmitted & received)/p(0 received)

= 0.45/0.525 = 6/7 ≈ 85.7%

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3 years ago

A) n(n + 2) 224b)x² + x = 156​