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andre [41]
3 years ago
9

Which two atoms form a covalent bond?

Biology
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

In a covalent bond, the atoms bond by sharing electrons. Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom.

Explanation:

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A food that supplies two grams each of fat, carbohydrate and protein delivers ___ total calories.
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<span>The commonly accepted values is 4 Calories per gram of protein and carbohydrate and 9 Calories per gram of fat. Since we have 2 grams of each, a little simple math will do: 2 g * 4 Cal/g + 2 g * 4 Cal/g + 2 g *9 Cal/g = 8 Cal + 8 Cal + 18 Cal = 34 Cal</span>
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Brainliest; please help me the picture is shown
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The answer is location.

Explanation:

The answer is very logical and need no explaination.

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3 0
3 years ago
Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of d
lidiya [134]

Answer:

42,5 mL

Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

DF=\frac{Vi}{Vf}

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

The first step is to have the same measurment unit so we need to convert 345 µg to mg.

we know that 1 µg equals 0,001 g, hence:

345 µg = 0,345 mg

now the final volume is 0,345 mg  protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula

DF= \frac{15mg protein/mL}{0.345mg protein/mL}

DF= 43,5 mg protein/ mL

Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

43,5mL-1,0mL = 42,5 mL

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)

8 0
3 years ago
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