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Sergio039 [100]
3 years ago
8

I need help doing my equation clock fully done or I report the first one done get brainlyest

Mathematics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:12,1,2,3,4,5,6,7,8,9,10,11

Step-by-step explanation:

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Write two numbers that have the given absolute value.<br><br> 22
ozzi

Answer:

22 and -22

Step-by-step explanation:

Absolute value means the distance of a number from zero

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Which order pair is the solution of the system of equations shown?ITS DUE TONIGHT HELP
kap26 [50]

Answer:

Step-by-step explanation:

-x + 5 = 5x - 6

-6x + 5 = -6

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answer is C

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You and a friend are playing a game by tossing two coins. If both coins land
Novosadov [1.4K]

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5 0
3 years ago
Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1
lyudmila [28]

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

3 0
3 years ago
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