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3 years ago

Giving brainliest !!! easy

Mathematics

2 answers:

Allisa [31]3 years ago

7 0

Answer:

(0,0) r=5

Step-by-step explanation:

Over [174]3 years ago

5 0

(0,0) r=5

I could be wrong but I’m sure it’s this

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Suppose that a college student is taking three courses: a two-credit course, a three-credit course, and a four-credit course. Th

forsale [732]

Answer:

The overall expected grade point average for the semester is 3.16/3.1 or 3.2 if you round it up.

Step-by-step explanation:

To get the average, you need to add up all the numbers then divide the sum by how many numbers you added.

3.5 + 3.0 + 3.0 = 9.5

9.5 / 3 = 3.16

4 0

2 years ago

Read 2 more answers

Just once i would like math to solve it's own problems,<br> i ain't no therapist.

Artyom0805 [142]

Answer:

brainly.com/question/22779054 PLEASE HELP ME

Step-by-step explanation:

5 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csf%20x-5%3D16" id="TexFormula1" title="\sf x-5=16" alt="\sf x-5=16" align="absmiddle" class

scZoUnD [109]

Answer:

Step-by-step explanation:

7 0

2 years ago

Teddy has two pairs of black shoes and three pairs of brown shoes. He also has one pair of brown pants and three pairs of black

horsena [70]

Answer:

0.20 or 20%

Step-by-step explanation:

Brown shoes = 3

Black shoes = 2

Total shoes = 5

Brown pants = 1

Black shoes = 3

Total pants = 4

Brown socks =4

Black socks = 6

Red socks = 2

Total socks = 12

In order to choose shoes, pants and socks of the same color, Teddy can go either all black or all brown. For all black, there is a 2 in 5 chance he gets the right shoes, 3 in 4 chance for pants and 6 in 12 for socks. For all brown, there is a 3 in 5 chance he gets the right shoes, 1 in 4 chance for pants and 4 in 12 for socks.

$P=P(All\ black)+P(All\ brown)\\P=\frac{2}{5}*\frac{3}{4}*\frac{6}{12}+ \frac{3}{5}*\frac{1}{4}*\frac{4}{12}\\P=0.20$

The probability that he chooses shoes, pants, and socks of the same color is 0.20 or 20%.

5 0

3 years ago

Giving brainliest !!! *easy*

Giving brainliest !!! easy