25 points answer it please Fast

The regular cost of a sound system is $1499, but today it is on sale for $1100! That is a $399 saving. The sales clerk tells you

andriy [413]

Answer:

$1456.48

Step-by-step explanation:

$37.68 x 3 months

37.68 x 36=1356.48

$1356.48 total over 3 yrs + $100 down= $1456.48

3 0

2 years ago

Which product is positive?

Natalija [7]

Option D:

$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$ is positive product.

Solution:

If the negative sign is in even number of times then the product is positive.

If the negative sign is in odd number of times then the product is negative.

To find which product is positive:

Option A:

$$\left(\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option B:

$$\left(-\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option C:

$$\left(\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative sign = 1

1 is an odd number.

So, the product is negative.

Option D:

$$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$

Here, number of negative sign = 2

2 is an odd number.

So, the product is positive.

Hence option D is the correct answer.

$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$ is positive product.

4 0

3 years ago

Find x and y please

Alexandra [31]

Answer:

Answer:

x → 4.24
y → 4.24

Step-by-step explanation:

» x and y can only be got through using trigonometric ratios:

✍ For x :

${ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ \\ { \tt{ \sin(45 \degree) = \frac{x}{6} }} \\ \\ { \tt{x = 6 \times \sin(45 \degree) }} \\ { \tt{x = 4.24}}$

✍ For y :

${ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( 45 \degree) = \frac{y}{6} }} \\ \\ { \tt{y = 6 \times \cos(45 \degree) }} \\ { \tt{y = 4.24}}$