From what i see, i guess the answer may be B. it looks like it, but i dont really know.
Y = 0 + 2
Since it is a horizontal line, the slope is m = 0.
For the y-intercept, the line passes through 2 so therefore, the y-intercept is 2 positive.
Wait, do you mean that y=10 is what you want in slope intercept form? Oh btw I'm not answering this just for the points. I'll actually answer the question
Step-by-step explanation:
focus(p) is on the x axis= -1
vertex=(0,0)
parabola equation----- (y-h)^2 =4p(x-k)
(h, k)=(0,0)
(y-0)^2 =4(-1)(x-0)
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y^2 = -4x
that is the answer
Step-by-step explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤
