Question

Mrs.Brooks lacks 7 from being fice times as old as her son. Six years from now she will lack 3 years from being three times as old as her son is then. Find each of their ages

Answer 1

Answer:

Step-by-step explanation:

Let the age of of Mrs brook be x

Age of her son be y

If Mrs.Brooks lacks 7 years from being five times as old as her son, this means;

x = 5y - 7 ..... 1

six years from now;

Mrs brooks age = x + 6

sons age = y + 6

If Six years from now she will lack 3 years from being three times as old as her son, this means;

x+ 6 = 3(y+6) - 3

x+6 = 3y + 18 - 3

x+6 = 3y + 15 .... 2

substitute 1 into 2;

(5y - 7)+6 = 3y + 15

5y - 1 = 3y + 15

5y-3y = 15 + 1

2y = 16

y = 8

substitute y = 8 into equation 1;

x = 5y - 7

x = 5(8)-7

x = 40-7

x = 33

Hence the mrs brook is 33 years old

her son is 8 years old