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2 years ago

14

Find the value of x in each pair of similar figures. Use proportions to solve.

1 answer:

Aleonysh [2.5K]2 years ago

8 0

Answer:

x=15

Step-by-step explanation:

3/5=9/x

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What property says that -12+12+0

natali 33 [55]

Answer:

Looks like <u>inverse property of addition </u>to me

4 0

3 years ago

Consider the following sequence

wlad13 [49]

Answer:

a₇ = 2.375

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

r = $\frac{-76}{152}$ = $\frac{38}{-76}$ = $\frac{-19}{38}$ = - $\frac{1}{2}$

This indicates the sequence is geometric with nth term

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 152 and r = - $\frac{1}{2}$ , then

$a_{n}$ = 152 $(-\frac{1}{2}) ^{n-1}$ , so

a₇ = 152 $(-\frac{1}{2}) ^{6}$ = 152 × $\frac{1}{64}$ = 2.375

3 0

3 years ago

Read 2 more answers

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

3 0

2 years ago

What f(5) if f(x) = -2x +1

Effectus [21]

F(5) is like X is 5
you just do this
f(5)=-2x+1
=-2(5)+1
=-10+1
= -9

:D

5 0

2 years ago

If i have 2 c's 2 A's 3 b's and 1 d what is my gpa and would i be able to pass 8th grade

IgorC [24]

A= 4 points
B= 3 points
C= 2 points
D= 1 point
F= 0 points

So you add 2+2+4+4+3+3+3+1
Which equals 22
Now divide 22 by 8
You get 2.75
So yes with a 2.75 gpa you should pass 8th grade as most schools require nothing less than a 2.0

8 0

3 years ago