Answer:
Ihorangi uses 7.65 litres of petrol to and from work
Step-by-step explanation:
If the car Ihorangi drives consumes 7.5 L/100 km
Then for 1 km journey, the car will consume 7.5/100 L
= 0.075 L
If Ihorangi travels 51 km to work and 51 km from work
Therefore Ihorangi travel (51 + 51) km daily to and from work
= 102 km daily
The fuel he consumes daily is 102*0.075 L
= 7.65 L
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
C. Because (-3)^2 is NOT equal to -9
Step-by-step explanation:
Answer:
5a + (-6a) + (-2b) + 2b + (-3) = -a -3 or -(a + 3) so first answer is correct because -(a + 3) is the same as -(3 + a)
Step-by-step explanation:
