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3 years ago

Kristen has 3/4

Mathematics

1 answer:

Snezhnost [94]3 years ago

3 0

Answer:

3/4 divide by 9 = 0.75/9 = 0.083 yard for each doll's hair ribbon

Step-by-step explanation:

Each doll's hair ribbon will be 0.083 (yards)

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Max went to the store and bought 22 apples. He bought twice as many red apples as he did green, and he bought one-third many yel

katrin [286]

Let the number of green apples bought be x

Green apples = x

Red apples = 2x

Yellow apples = 1/3 (2x) = 2/3 x

Total = 22 apples

x + 2x + 2/3 x = 22

11/3 x = 22

11x = 66

x = 6

Green apples = x = 6

Red apples = 2x = 2(6) = 12

Yellow apples = 2/3 (2x) = 2/3 (6) = 4

Answer: Green = 6, Red = 12, Yellow = 4

7 0

3 years ago

Tres compañías de navegación pasan por cierto puerto. La primera cada 8 días; la

lilavasa [31]

I think this is a least common multiple question

So they would all arrive on day 504, (which probably is a few years)

8 = 2 × 2 × 2

18 = 2 × 3 × 3

21 = 3 × 7

I might be right I might be wrong, IM not positively sure but yknow

4 0

3 years ago

Make r the subject of x= e + r/d

neonofarm [45]

Step-by-step explanation:

X=e+r/d

swap both sides

e+r/d=x

subtract e from both sides

e-e+r/d=x-e

r/d=x-e

multiply d to both sides

d×r/d=x-e×d

r=x-e×d

7 0

3 years ago

-7πh = 98π <br> solve for h

ICE Princess25 [194]

Answer:

h = -14

Step-by-step explanation:

-7πh = 98π

⇔ -7h = 98 (Just Divide both sides by π)

⇔ h = 98 ÷ (-7) = -14

5 0

1 year ago

Read 2 more answers

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$

Follow the above procedure will give the vertex form.

(NOTE : you must know that $\mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}$ . Use this equation in transforming the equation from step 3 to step 4)

8 0

3 years ago