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2 years ago

What is the value of x in the equation 3x-4y=65 when y =4

1 answer:

5 0

3x - 4(4) = 65

First, simplify 4 × 4 to get 16. / Your problem should look like: 3x - 16 = 65
Second, add 16 to both sides. / Your problem should look like: 3x = 65 + 16
Third, simplify 65 + 16 to 81. / Your problem should look like: 3x = 81
Fourth, divide both sides by 3. / Your problem should look like: x = $\frac{81}{3}$
Fifth, simplify $\frac{81}{3}$ to 27. / Your problem should look like: x = 27

Answer: x = 27

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To increase an amount by 17.5% what single multiplier would you use?

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You would multiply that number by 1.175

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2 years ago

A Statistics professor has observed that for several years students score an average of 106 points out of 150 on the semester ex

tekilochka [14]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 106

For the alternative hypothesis,

µ > 106

It is a right tailed test because of >.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 241,

Degrees of freedom, df = n - 1 = 241 - 1 = 240

t = (x - µ)/(s/√n)

Where

x = sample mean = 109

µ = population mean = 106

s = samples standard deviation = 8.3

a) test statistic, t = (109 - 106)/(8.3/√241) = 5.61

We would determine the p value using the t test calculator. It becomes

p = 0.00001

Since alpha, 0.05 > than the p value, 0.00001, then we would reject the null hypothesis. Therefore, At a 5% level of significance, this improvement seem to be practicallysignificant.

b) Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

n = number of samples

From the information given, the population standard deviation is unknown, hence, we would use the t distribution to find the z score

df = 240

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 1.6512

Margin of error = 1.6512 × 8.3/√241

= 0.88

Confidence interval = 109 ± 0.88

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2 years ago

how would a enter a payment that was accepted with a 4 month, 8% note in a payment of a $4800.00 account

Anon25 [30]

Answer:

Enter a payment of 5192.52.

Step-by-step explanation:

Consider the provided information.

The payment is $4800 with a 4 month, 8% note.

The amount can be calculated as:

$Amount=p(1+\frac{r}{m})^{mt}$

Where p is money invested, r is annual interest rate, t is number of years and m is number of period.

Now substitute p = 4800 r = 0.08 and m = 4 in the above formula.

$Amount=4800(1+\frac{0.08}{4})^4$

$Amount=4800(1+0.02)^4$

$Amount=4800(1.02)^4$

$Amount=4800(1.08243216)$

$Amount=5195.52\ approximately$

Hence, enter a payment of 5192.52.

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2 years ago