Answer:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
x = 5 x = 4
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
This is right belive me
Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Answer:
a) C(x) = 15000/x + 6x +80
b) Domain of C(x) { R x>0 }
Step-by-step explanation:
We have:
Enclosed area = 1500 ft² = x*y from which y = 1500 / x (a) where x is perpendicular to the river
Cost = cost of sides of fenced area perpendicular to the river + cost of side parallel to river + cost of 4 post then
Cost = 10*y + 2*3*x + 4*20 and accoding to (a) y = 1500/x
Then
C(x) = 10* ( 1500/x ) + 6*x + 80
C(x) = 15000/x + 6x +80
Domain of C(x) { R x>0 }
