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Flauer [41]
2 years ago
5

In City Park, the playground takes up 3/8 of the area. The soccer field area is 1/3 of the playground area. The product 13×38 ca

n be used to find the area of the soccer field. Which is the area of the soccer field?
Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
3 0

The area of the city park will be equal to 3952 square units.

<h3>What is the area?</h3>

The Area is defined as the space occupied by the two-dimensional geometry in a plane.

We have the following information:-

In City Park, the playground takes up 3/8 of the area:-

\rm PGA=\dfrac{3}{8}\times CP

The soccer field area is 1/3 of the playground area.

\rm SF=\dfrac{1}{3}\times PGA

The product 13×38 can be used to find the area of the soccer field

SF= 13  x  38=494 square units

Noe the PGA will be:-

PGA =3 x SF

PGA= 3 x494=1482 square unit

Now the area of the city park will be calculated as:-

\rm CP=\dfrac{8}{3}\times PGA\\\\\\CP=\dfrac{8}{3}\times 1482

CP=3952 square unit

Hence the area of the city park will be equal to 3952 square units.

To know more about the area follow

brainly.com/question/24375372

#SPJ1

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A rectangular photograph is nine centimeters wide and fourteen centimeters long. The photograph is enlarged by increasing the le
koban [17]

Answer:

Width=13cm

Length=18cm

Step-by-step explanation:

Width of the Initial Photograph=9cm

Length of the Initial Photograph=14cm

If width and length are increased by an equal amount, say x

New Width=9+x

New Length=14+x

Area of the new photo is 108 square centimeters greater than the area of the original photo.

Area of Original Photo=14*9=126cm²

Aeea of the New Photo=126+108=234cm²

Therefore:

(9+x)(14+x)=234

126+9x+14x+x²-234=0

x²+23x-108=0

x²+27x-4x-108=0

x(x+27)-4(x+27)=0

(x+27)(x-4)=0

x+27=0 or x-4=0

x=-27 or x=4

Since x≠-27

x=4cm

The dimensions of the new photo are:

Width=9+x=9+4=13cm

Length=14+x=14+4=18cm

4 0
3 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
2 years ago
3y+2=5(y-6) please help :)
grigory [225]
In this problem, y = 16!
4 0
3 years ago
Read 2 more answers
Which equation is the inverse of y = x² - 36?
Damm [24]
Answer:
y = SQRT( x + 36 )
y = - SQRT( x + 36 )

Steps:
The 5 options you listed are unclear to me. But I provided the correct answer above.
4 0
1 year ago
The time a traffic light remains yellow is one second more than 0.05 times the speed limit. What is the yellow time for a traffi
weqwewe [10]
30 * 0.05 + 1 = X
1.5 + 1 = X
2.5 = X

The light remains yellow for 2.5 seconds on a street with a speed limit of 30.
4 0
2 years ago
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