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Maksim231197 [3]
2 years ago
12

Chelsea plays soccer 4/12 of the year and swims 3/12 of the year before taking a break from playing sports what fraction of the

year does Chelsea spend participating in sports
Mathematics
1 answer:
Kay [80]2 years ago
4 0

Answer: 7/12

Step-by-step explanation:

From the question, we are told that Chelsea plays soccer 4/12 of the year and swims 3/12 of the year before taking a break from playing sports.

The fraction of the year that Chelsea spend participating in sports will be the addition of the fraction used for playing soccer and the fraction use for swimming. This will be:

= 4/12 + 3/12

= 7/12

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pogonyaev

To find their average miles per hour we can divide the total miles by the hour used:

4 2/3 ÷ 1 2/3

=4x3+2/3 ÷ 1x3+2/3

=14/3 ÷ 5/3

In division, when we switch the place of numerator and denominator, we can change it to multiplication which makes the calculation easier as we can factorize the numbers.

=14/3 x 3/5

Factorize 3 in both amounts:

=14/1 x 5/1

=14/5

=2.8 miles/hour

Therefore their average speed is 2.8 miles/hour.

Hope it helps!

8 0
2 years ago
a punch recipe says to mix 4 cups pineapple juice,8 cups orange juice,and 12 cups seltzer in order to make 18 servings of punch.
patriot [66]

2/3 cups of pineapple juice, 4/3 cups of orange juice and 2 cups of seltzer for 3 servings.

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Apply the Pythagorean Theorem to find the distance between points A and C.
Rashid [163]

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Step-by-step explanation:

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3 years ago
-73 greater than or equal to 15 + 11x
Alecsey [184]
-73 ≥ 15 + 11x 
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-73 -15 ≥ 11x 
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5 0
3 years ago
Read 2 more answers
Unghiurile ∢AOB, ∢BOC, ∢COD și ∢DOA sunt unghiuri în jurul punctului O, ∢AOB = 80°, ∢BOC = 140° și CO ⊥ OD.
Sonbull [250]

Answer:

a) ∡AOC = 140 °

∡AOD = 40 °

b) ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC (unghiuri formate din segmentul OC) prin urmare, segmentul OC bisectează ∡AOB

Step-by-step explanation:

a) Calculați măsurile unghiurilor ∢AOC și ∢AOD.

b) Arătați că jumătatea liniei opuse jumătății liniei OC este bisectoarea unghiului ∢AOB

a) Parametrii dați sunt;

∡AOC. ∡BOC. ∡COD și ∡DOA sunt unghiuri în jurul circumferinței unui cerc

∡AOB = 80 ° și ∡BOC = 140 °, segmentul CO este perpendicular pe segmentul DO

Prin urmare, avem;

∡AOB + ∡BOC + ∡AOC = 360 ° (Suma unghiurilor într-un punct = 360 °)

∴ ∡AOC = 360 ° - (∡AOB + ∡BOC) = 360 ° - (80 ° + 140 °) = 140 °

  ∡AOC = 140 °

∡BOC + ∡BOD = 180 ° (Suma unghiurilor unui triunghi = 180 °)

∡BOD = 180 ° - ∡BOC = 180 ° - 140 ° = 40 °

∡BOD = 40 °

∡ BOD + ∡AOD = ∡AOB

∡AOD = ∡AOB - ∡BOD = 80 ° - 40 ° = 40 °

∡AOD = 40 °

b) Deoarece avem ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC = 140 °, avem;

∡AOB = 140 ° + 140 ° = 280 ° = 2 × ∡BOC = 2 × ∡AOC

Prin urmare, segmentul OC bisectează ∡AOB

3 0
3 years ago
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