Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
percent 88%
fraction 44/50
ratio 44:50
Step-by-step explanation:
Answer:
Step-by-step explanation:
c
Answer:
The answer to your question is y - 0 = 40(x - 15)
Step-by-step explanation:
y = 40x + 600
Convert to y - y₁ = m(x - x₁)
Process
1.- Factor 40 in the right side of the equation
y = 40(x - 15)
2.- Give the form of the point slope form
y - 0 = 40(x - 15)
where
y₁ = 0
m = 40
x₁ = 15