Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
25
Step-by-step explanation:
1.add 30+8+9000000•84-36/x
2. 756000034.4
3. Subtract 174374985634-756000034.4
Answer:1.736189856E11
Answer:
4 chocolates
Step-by-step explanation:
Since the problem states that the girl received a "giant box", this situation can be treated as if there is replacement, since the change in the probability of getting a chocolate with fruit filling would be minimal after picking a random chocolate.
Therefore, the expected number of choices she has to make before finding the first fruit flavored one is obtained by dividing 1 by the probability of a fruit flavored one:
She should expect to choose 4 chocolates.