Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
72 N
Step-by-step explanation:
From the question.
Force is directly proportional to acceleration, with the mass of the object constant.
F α a
F = ka
F₁/a₁ = F₂/a₂....................... Equation 1
Where F₁ = Initial force, a₁ = initial acceleration. F₂ = final force, a₂ = Final acceleration.
make F₂ the subject of the equation
F₂ = (F₁/a₁)a₂................ Equation 2
Given; F₁ = 64 N, a₁ = 8 m/s², a₂ = 9 m/s²
Substitute these values into equation 2
F₂ = (64/8)(9)
F₂ = 72 N
Answer:
see the explanation
Step-by-step explanation:
we know that
The y-intercept is the value of the function y when the value of x is equal to zero
Part 1) we have
For x=0
substitute in the linear equation and solve for y
therefore
The y-intercept is the point (0,-6)
Part 2) Find the y-intercept of the function represented in the graph
Looking at the graph
For x=0
Find the value of y in the graph
The value of y is equal to y=1
therefore
The y-intercept is the point (0,1)
Answer:
B: Survey 3 randomly selected students from every homeroom.
Step-by-step explanation:
This would be the best way to survey, because all the others have some sort of variable. The principle doesn't know who buys lunch and who doesn't, so why would he just ask kids who ride in a car as there are kids who ride buses, or only 7th grade students, so the best answer would be something that everyone has, like homeroom.