Sides of first rectangle are 12 inches and 6 inches
and sides of second rectangle are 10 inches and 5 inches
So to find the ration of sides we can do
Ratio of bases = 12/10 = 6/5
Ratio of altitudes = 6/5
Area of first rectangle = base * altitude = 12 *6 = 72 square inches
Part A
<h3>Answer:
h^2 + 4h</h3>
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Explanation:
We multiply the length and height to get the area
area = (length)*(height)
area = (h+4)*(h)
area = h(h+4)
area = h^2 + 4h .... apply the distributive property
The units for the area are in square inches.
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Part B
<h3>Answer:
h^2 + 16h + 60</h3>
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Explanation:
If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.
Similarly, along the vertical side we'd have the h go to h+3+3 = h+6
The old rectangle that was h by h+4 is now h+6 by h+10
Multiply these expressions to find the area
area = length*width
area = (h+6)(h+10)
area = x(h+10) ..... replace h+6 with x
area = xh + 10x .... distribute
area = h( x ) + 10( x )
area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6
area = h^2+6h + 10h+60 .... distribute again twice more
area = h^2 + 16h + 60
You can also use the box method or the FOIL rule as alternative routes to find the area.
The units for the area are in square inches.
Answer:
b) 9x² - 3x
Step-by-step explanation:
Area of a rectangle = Length × Width
Area for the rectangle = 3x - 1 × 3x
Area = 
Step 1. Multiply by combining like terms
3x · 3x = 9x²
Step 2. Multiply -1 by 3x
-1 · 3x = -3x
Step 3. Combine 9x² and -3x
9x² - 3x
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doomdabomb: All brainliest and thanks are appreciated
and would mean a lot to me, thanks!
You need to isolate the variable my dividing each side by factors that don’t contain the variable
x=-5
