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kati45 [8]
3 years ago
5

What is 100 rouned to the nearest thousandths ​

Mathematics
2 answers:
poizon [28]3 years ago
4 0

Answer:

0

Step-by-step explanation:

Rounding down from 100 to the nearest thousand is 0.

Vladimir [108]3 years ago
4 0

Answer:

0

Step-by-step explanation:

0.1 rounds to 0

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Which of the following rules describes the function graphed below?
n200080 [17]

Answer:

D

Step-by-step explanation:

Output = 3*input - 2. Observe the graph again

4 0
2 years ago
Find the value of x and y​
Marianna [84]

Answer:

What is the equation?

Step-by-step explanation:

6 0
3 years ago
I need help ASAP, with numbers 3-6 above. Please help.
MatroZZZ [7]

Answer:

3. 2 6 30          6. 8:5

   3 9 45

Step-by-step explanation:

6 0
3 years ago
If standard deviation of a given data is 5 and mean is 50 then coefficient of variation (C.V) is equal to *
torisob [31]

Answer:

10

Step-by-step explanation:

Coefficient of variation is a measure of dispersion, showing the variability of data in relation to the mean.

The Coefficient of variation compares the degree of variation between data points. The coefficient of variation is the ratio of mean to standard deviation. It is given by the formula:

Coefficient of variation = mean / standard deviation

Coefficient of variation = 50 / 5

Coefficient of variation = 10

4 0
3 years ago
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