If sarah starts her chores at 10:15

If f(x) is an exponential function where f(-1.5) 26 and

mariarad [96]

Answer:

$f(10) = 1147.25$

Step-by-step explanation:

Given

$f(-1.5) = 26$

$f(5.5) = 7$

Required

f(10)

An exponential function is represented as:

$f(x) = ab^x$

$f(-1.5) = 26$ impleies that:

$26 = ab^{-1.5}$ --- (1)

$f(5.5) = 7$ implies that

$7 = ab^{5.5}$ --- (2)

Divide (2) by (1)

$26/7 = ab^{-1.5}/ab^{5.5}$

$3.71429 = b^{-1.5+5.5}$

$3.71429 = b^{4}$

Take 4th root

$b = 1.39$

Substitute $b = 1.39$ in $26 = ab^{-1.5}$

$26 = a * 1.39^{-1.5}$

$26 = a * 0.6102$

Solve for (a)

$a = 26/0.6102$

$a = 42.61$

f(10) is calculated as:

$f(10) = ab^{10}$

$f(10) = 42.61 * 1.39^{10}$

$f(10) = 1147.25$

3 0

2 years ago

Please help me. if you can help me answer multiple questions only 3. offering 30 points for it

lubasha [3.4K]

Answer:

(-9, -5)

Step-by-step explanation:

Ok, so when you move an image to the right, you are moving along the x-axis, and when you move up, you are moving up the y-axis. So if the altered image is (x,y) and the values are (-5, -1), you reverse what has been done to the image. In this case, since we moved to the right 4 units, we know that means we added 4 to x, so we subtract 4 to get -9. And then, for the y-value, because we added 4, we do the opposite, and subtract 4 to get -5. So the pre-image should be (-9, -5)

7 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$