Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
The ratio would be 8:20 or 8 to 20
V = u + at
u = 0
v = 0 + 1.5*5
v = 7.5 m/s
final velocity is 7.5 m/s
s = ut + 0.5at^2
s = 0 + (0.5*1.5*5^2)
s = (0.5*1.5*25)
s = 18.75 m
total travel distance is 18.75 m.
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span> 6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0
</span><span>Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 6x2-x-4</span>
The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span>
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is <span> -1 </span>.
<span><span> -24 + 1 = -23</span><span> -12 + 2 = -10</span><span> -8 + 3 = -5</span><span> -6 + 4 = -2</span><span> -4 + 6 = 2</span><span> -3 + 8 = 5</span><span> -2 + 12 = 10</span><span> -1 + 24 = 23
</span></span>
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span><span> 6x2 - x - 4 = 0 </span>
If you meant to write y=23x-4 then none of the lines are perpendicular.
I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.
For any line y=mx+b, you have to "invert" m to get a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.
So 2/3 becomes -3/2, hence answer D.
The 'inverted' m is called the opposite reciprocal. That's your word of the day.
