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Minchanka [31]
3 years ago
14

I need help please!!!! No links aloud

Mathematics
1 answer:
Verdich [7]3 years ago
7 0

Answer:

the second one.

Step-by-step explanation:

You might be interested in
Write 6600 as a product of its prime factors. (show your working out)
dem82 [27]

Answer: 2 × 3 × 5 × 11 = 330.

Step-by-step explanation: Since, the prime factors of 6600 are 2, 3, 5, 11. Therefore, the product of prime factors = 2 × 3 × 5 × 11 = 330.

8 0
3 years ago
Help me pls i am begging.
ioda

Answer:

-4

Step-by-step explanation:

-4 x 13 = -52

Hope that helps :)

4 0
2 years ago
Five friends want to rent a go-cart track that costs $100. Each friend intends to contribute the same about.
Inessa [10]
Just divide $100 by 5. 100 divided by 5 = $20 each.
6 0
3 years ago
(Set up and solve the system, then answer the associated question)
Dimas [21]

9514 1404 393

Answer:

  • red division: 6 teams
  • blue division: 5 teams

Step-by-step explanation:

We can let r and b represent the numbers of teams in the red and blue divisions, respectively. The total number of goals scored in each division will be the average for that division times the number of teams in that division.

  r - b = 1 . . . . . . there is 1 more red team than blue

  4.5r +4.2b = 48 . . . . . . total goals scored per week

__

Solving by substitution, we have ...

  r = b +1

  4.5(b +1) +4.2b = 48 . . . . substitute for r

  8.7b +4.5 = 48 . . . . . . . . simplify

  8.7b = 43.5 . . . . . . . . . . subtract 4.5

  b = 43.5/8.7 = 5 . . . . . divide by 8.7

  r = b +1 = 6 . . . . . . . . . find r

There are 6 red teams and 5 blue teams.

_____

<em>Additional comment</em>

The basic idea is that you make an equation for each relation given in the problem statement. For a problem like this, you do need to have an understanding of how the average number of goals would be calculated and how that relates to the total goals.

8 0
2 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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