What is the measure compliment for 57 degrees

1 answer:

7 0

To find this, simply subtract 57 from 90. 90 is the measurement for a completed compliment equation, and 57 is the part of the compliment we know.

33 is the answer

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A+ 2b = 10 2a + b =6

GenaCL600 [577]

First you can solve for b: Subtract a on both sides and get 2b=-a+10, then divide by 2 to get b by itself and get: b=-1/2a+5

Then you can plug in this equation for b in the other: This would give you: 2a+-1/2a+5=6. Then you can use that equation to solve for a and get: 1.5a+5=6, subtract 5, 1.5a=1, divide by 1.5, a=1/1.5

Then you can plug in the value of a to solve for b.

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3 years ago

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Why did Chase (and many others) oppose passage of the Kansas-Nebraska Act?

Misha Larkins [42]

Some objected to slavery on moral grounds, believing that it violated christian teachings , while others simply did not want to complete economically with slave-owners.

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2 years ago

Which of the following proportions is false? 10/25 = 40/100 24/30 = 20/25 18/48 = 20/50 25/45 = 75/135

Liono4ka [1.6K]

Answer:

18/48=20/50 is wrong

Step-by-step explanation:

Because 18/48=37.5% and 20/50=40%

Hope it helps

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2 years ago

H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

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3 years ago

vivi is a drummer for a band. she burns 756 calories while drumming for 3 hours. she burns the same number of calories each hour

Airida [17]

Answer:

252 cph

Step-by-step explanation:

756 divide by 3 is 252

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3 years ago