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zimovet [89]
3 years ago
10

How does the answer to each multiplication problems answer to is a corresponding division problem

Mathematics
1 answer:
Llana [10]3 years ago
5 0
Because they are math buddies say 2x2=4. You can divide 4÷2 and get your original factor (2)... Sorry if it's wrong I think that's what it means ,hope it helps!
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Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
lina2011 [118]

Answer: Hewo, there! your answer is Below

a 90 clockwise rotation about the origin and a reflection over the y-axis

Step-by-step explanation:

Hope this helps you !!!

Have a great day!!!

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3 years ago
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Approximately 10% of all people are left-handed. Consider a grouping of fifteen people.
Wewaii [24]

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Step-by-step explanation:

6 0
2 years ago
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Given right triangle ABCABC with altitude \overline{BD}
Alex

Answer:

x = 2\sqrt{11}

Step-by-step explanation:

AD = 4

AC = 11

DC = 11 - 4 = 7

First, find BD using the right triangle altitude theorem:

BD = \sqrt{AD*DC}

Plug in the values

BD = \sqrt{4*7}

BD = 2\sqrt{7}

Use pythagorean theorem to find x:

x² = AD² + BD²

Plug in the values

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 16 + (4*7)

x^2 = 16 + 28

x^2 = 44

Take the square root of both sides

\sqrt{x^2} = \sqrt{44}

x = \sqrt{44}

x = \sqrt{4 * 11}

x = 2\sqrt{11}

6 0
3 years ago
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(-2 √(-49)(5 √(-100)
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Answer:

The answer is... 700

4 0
2 years ago
A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred
Sergio039 [100]

Answer:  0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = \dfrac{0.63}{3}

=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

2\times0.21=0.42\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

6 0
3 years ago
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