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2 years ago

Rewrite each expression in terms of sine and cosine only.

Mathematics

1 answer:

Sliva [168]2 years ago

6 0

Answer:

1. Cosθ / SineθCosθ

2. Sineθ / Cos²θSineθ

3. Cosθ / Sineθ

4. Cos²θ + Sin²θ – Sin²θ

Step-by-step explanation:

1. SecθCotθ

Recall

Sec θ = 1/Cos θ

Cot θ = 1/Tan θ

But Tan θ = Sine θ / Cos θ

Thus,

Cot θ = 1 ÷ Sine θ / Cos θ

Cot θ = 1 × Cos θ / Sine θ

Cot θ = Cos θ / Sine θ

Therefore,

SecθCotθ = 1/Cos θ × Cos θ / Sine θ

SecθCotθ = Cosθ / SineθCosθ

2. SecθTanθCscθ

Recall

Sec θ = 1/Cos θ

Tan θ = Sine θ / Cos θ

Csc θ = 1/Sine θ

Thus,

SecθTanθCscθ =

1/Cosθ × Sineθ/Cosθ × 1/Sineθ

= Sineθ / Cos²θSineθ

3. Cscθ/Secθ

Recall

Csc θ = 1/Sine θ

Sec θ = 1/Cos θ

Thus,

Cscθ/Secθ = 1/Sine θ ÷ 1/Cos θ

= 1/Sine θ × Cos θ

= Cosθ / Sineθ

4. Cosθ / Secθ

Recall

Sec θ = 1/Cos θ

Cosθ / Secθ = Cosθ ÷ 1/Cosθ

= Cosθ × Cosθ

= Cos²θ

Recall

Cos²θ + Sin²θ = 1

Cos²θ = 1 – Sin²θ

But

1 = Cos²θ + Sin²θ

Thus,

Cos²θ = Cos²θ + Sin²θ – Sin²θ

Therefore,

Cosθ / Secθ = Cos²θ + Sin²θ – Sin²θ

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siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be $x.$

So, 54 is equivalent to 36.

Thus, 17 is equivalent to $x.$

$\frac{54}{36} =\frac{17}{x}$

By cross multiplying we get:

$54x=612$

Dividing both sides by 54 we get:

$x=11.33\ inches.$

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= $54\times 36:17\times 11.33$

= $1944:192.61$

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

6 0

3 years ago

Read 2 more answers

8+2(5 - x) = Need help

nikdorinn [45]

We can distribute
2(5)+2(-x)=10-2x

we get
8+10-2x=?
18-2x=?

whatever that ? is, we don't know
multiply both sides by -1
2x-18=-?
add 18 to both sides
2x=18-?
divide bth sides by 2
x=9-(?/2)
whatever the left side it, just divide it by 2 and subtract it from 9

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3 years ago

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DochEvi [55]

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Explanation:

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julsineya [31]

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