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Marina CMI [18]
3 years ago
10

100m In 9 3/5 seconds

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

Speed = 10.42 m/secs

Step-by-step explanation:

We have been given with:-

Distance = 100m

Time taken = 9\frac{3}{5} secs

1) First, we need to convert the mixed number 9\frac{3}{5} to an improper fraction.

<u>Method to convert a mixed number to an improper fraction</u>

<u>a\frac{b}{c} = \frac{c*a+b}{c}</u>

Applying the above formula, we get

9\frac{3}{5} = \frac{5*9+3}{5}

= \frac{45+3}{5}

= \frac{48}{5}

2) Now we need to convert \frac{48}{5} into a decimal by dividing 48 by 5.

We get time taken as 9.6 secs

3) We need to find the speed using the below formula:-

Speed = \frac{Distance}{Time taken}

Plugging the values of Distance and Time taken into the formula, we get

Speed = \frac{100}{9.6}

= 10.416 m/secs

4) Upon rounding it to the nearest hundredth, we get

Speed = 10.42 m/secs

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(x1/6)3 simplify the expression
svp [43]

Answer:

x1/2

Step-by-step explanation:

Simplify the following:

(3 x1)/6

Hint: | In (x1×3)/6, divide 6 in the denominator by 3 in the numerator.

3/6 = 3/(3×2) = 1/2:

Answer:  x1/2

6 0
3 years ago
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I need to know the solution to this
Alex73 [517]
There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate

Look at equation 1, -2x+y=10 this can quite easily be manipulated to show y=10+2x.

Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one 4x-y=-14 \Rightarrow 4x-(10+2x)=-14 which can then be solved for x since there is only one variable 4x-10-2x=-14 \Rightarrow 2x=-4 \Rightarrow x=-2 and then with our x solution we can work out our y solution by using the equation we manipulated y=10+2x = 10+(2 \times -2) = 10-4=6.

So the solution to these equations is x=-2 when y=6
8 0
3 years ago
0+4=?<br> Help will be needed here
Romashka [77]

Answer:

40

you add a 0 to the four and boom

If you are really asking, then the answer is still 4

8 0
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Please help asap! explaining how you got the answer will give you brainliest.
xeze [42]
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7 0
2 years ago
The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle​
AVprozaik [17]

Answer:

  • Length of rectangle is 31 yards and Width is 24 yards.

Given:

  • The length of a rectangle is 7 more than the width.
  • The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

\\  \:  \:  \:  \:  \pink{ \dashrightarrow \:  \:  \:  \:  \sf { \underbrace{Area_{(Rectangle)} =  Length × Width  }}} \\  \\

On Substituting the required values, we get;

\\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x - 744 = 0 \\ \\ \\  \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x = 24 \:  or \:   - 31 \\ \\

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

  • Width of rectangle = x = 24 yards
  • Length of the rectangle = x + 7 = 31 yards

\thereforeLength of rectangle is 31 yards<u> </u>and Width is 24 yards.

8 0
2 years ago
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