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tester [92]
2 years ago
6

Can someone write an equation out of X= -4 Y= -8 Z= 3

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
4 0

Answer:

2y + 4z = x

Step-by-step explanation:

Given

x = -4

y = -8

z = 3

Required

Write an equation that which is true for the above parameters

<em>This question will be answered using trial by error method and the solution is not limited to one equation.</em>

<em></em>

One equation that matches the values above is:.

2y + 4z = x

To check:

Substitute the values of x, y and z in the above equation.

2y + 4z = x

2 * -8 + 4 * 3 = -4

-16 + 12 = -4

-4 = -4

Hence,

Because both sides of the equation are one and the same (-4), 2y + 4z = x is true for the above values of x, y and z.

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pychu [463]

Answer:

<u>⅓</u>

<h2>Step-by-step explanation:</h2>

\frac{5}{9}  \times  \frac{3}{5}

=  \frac{1}{3}  \times  \frac{1}{1}

=  \frac{1}{3}

<h2>Checking:</h2>

\frac{1}{3}  \div  \frac{3}{5}

=  \frac{1}{3}  \times  \frac{5}{3}

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#CarryOnLearning

8 0
3 years ago
Read 2 more answers
Please help whats the answer !!?
Soloha48 [4]

The correct answer is the one on the top right corner.

3 0
2 years ago
A triangle with vertices (0, 4), (3, 7) and (5, 1) is translated a distance of 4 units to the left. What are the new coordinates
STALIN [3.7K]
The new coords are (-4, 4), (-1,7) and (1,1)
5 0
3 years ago
A boat takes 4 hours to go 20 miles upstream. It can go 32 miles downstream in the same time. Find the rate of the current and t
KonstantinChe [14]
Let the boat speed in still water be b.
Let the current speed be c.
The speed going upstream is 20/4 = 5 mph.
The speed going downstream is 32/4 = 8 mph.
b - c = 5 ........(1)
b + c = 8 .......(2)
Adding equations (1) and (2) we get:
2b = 13
b = 13/2 = 6.5
Plugging in the value for b into equation (1) we find c = 1.5.
The boat speed in still water is 6.5 mph and the current speed is 1.5 mph.
4 0
2 years ago
Help please and explain
tresset_1 [31]

Answer:

30 ft

Step-by-step explanation:

We can use ratios

3              6

------ = ------------

15            x

Using cross products

3x = 6*15

Divide each side by 3

3x/3 = 6*15/3

x = 30

5 0
3 years ago
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