Answer:
domain={-5,-3,0,2}
range={0,2,4,7}
Step-by-step explanation:
yes
Answer:Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Answer:
3p² + 32p + 13
Step-by-step explanation:
Okay, so lets first solve for 2b. 2b = 2(p + 5), which is equal to 2p + 10. Now, let's solve for 3a. 3a = 3(p² + 10p +1), simplifying to 3p² + 30p +3. After adding 2b and 3a, we are able to get 2p + 10 + 3p² + 30p + 3 = 3p² + 32p + 13
let the 2 integers be x and x + 2.
so we have the equation:-
3(x + 2) = x - 10
3x + 6 = x - 10
2x = -16
x = -8
the integers are -8 and -6 answer
