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zmey [24]
2 years ago
5

Write a quadratic function f whose only zeros are -3 and -12

Mathematics
1 answer:
emmasim [6.3K]2 years ago
3 0

Answer:

Step-by-step explanation:

f(x) = (x + 3)(x + 12)

f(x) = x^2 + 3x + 12x + 36

f(x) = x^2 + 15x + 36

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Solve the equation-4(x+10)-6=-3(x-2)<br>​
marta [7]

Answer:

x = -52

Step-by-step explanation:

-4x-46+46=-3x+6+46

-4x=-3x+52

-4x+3x=-3x+52+3x

8 0
2 years ago
Read 2 more answers
How do you write 41.344 in word form
Semenov [28]

Answer:

forty one point three hundred and forty four

Step-by-step explanation:

4 0
3 years ago
What would be the answer? Or how do I solve it?
stellarik [79]

AB = √(8^2 + 6^2)

AB = √100

AB = 10

AC = √(8^2 + 15^2)

AC = √289

AC = 17

BC = 9

P= AB + AC + BC

P = 10 + 17 + 9

P = 36 units

34)

Area of ABC = 1/2 x 8 x 9

A = 36 square units

6 0
3 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
3 years ago
Write an equation of the line in point-slope form that passes through the given points (-3,2) (5,5)
daser333 [38]
I think it is: y=0.375x+3.125

a=(5-2)/(5- -3)=3/8=0.375

Find b

(5)=0.375(5)+b
(5)=1.875+b
5-1.875=b
b=3.125
3 0
2 years ago
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