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2 years ago

5x -6y=-32

1 answer:

3 0

So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)

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A cone with a volume of 640.23 has a radius of 7. What is the height of the cone?

USPshnik [31]

Answer:

Your answer is about 12.48

Step-by-step explanation:

h = 3(V/pi*r²)

h = 3(640.23/pi*7²)

h = 3(640.23/153.93804)

h = 3(4.157516881)

h = 12.47703

8 0

2 years ago

Does anyone know the answer to this?

PolarNik [594]

Answer:

(B) The exponents should be subtracted by the quotient rule of exponents

Step-by-step explanation:

Let's examine how this was solved.

$(\frac{4^2 4^3}{4^{-5}})^2$

He first rose everything in the parentheses to the second power, which is just multiplying all the exponents by 2. This is correct.

$\frac{4^4 4^6}{4^{-10}}$

He then combined the numerator exponents. Exponent rules say that $a^b \cdot a^c = a^b+c$ , so he should have ended up with $4^{10}$ , which he did. This is correct.

$\frac{4^{10}}{4^{-10}}$

Now, what he did in the final step is wrong. He added the exponents. However, exponent rules tell us that when we have $\frac{a^b}{a^c}$ , it equals $a^{b-c}$ .

$10 - (-10) = 10+10 = 20$

So the final answer should have been $4^{20}$

Hope this helped!

6 0

3 years ago

What is the range of the cubic function f(x)=x^3-15

Nina [5.8K]

B

The end behavior of a positive cubic function states that as x approaches infinity, y approaches infinity.

Similarly, as x approaches negative infinity, y approaches negative infinity.

This means that when written in interval notation, the range is (-inf, +inf).

3 0

2 years ago

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand co

kobusy [5.1K]

So, the first brand has 9% vinegar, and say we use "x" amount of it, then, the amount of vinegar in "x" is 9% of x, or (9/100) * x, 0.09x.

the second brand has 14% of vinegar, and if we use say "y" amount of it, then the amount of vinegar in "y" is really just 14% of "y" or, (14/100) * y, 0.14y.

$\bf \begin{array}{lccclll}
&\stackrel{mL}{amount}&\stackrel{\%}{concentration}&\stackrel{amount}{concentration}\\
&------&------&------\\
\textit{first brand}&x&0.09&0.09x\\
\textit{second brand}&y&0.14&0.14y\\
------&------&------&------\\
mixture&230&0.13&29.9
\end{array}$

so, whatever "x" and "y" are, we know that x + y = 230.

and we also know that their concentration amounts will also add up, 0.09x + 0.14y = 29.9.

$\bf \begin{cases}
x+y=230\implies \boxed{y}=230-x\\
0.09x+0.14y=29.9\\
----------\\
0.09x+0.14\left(\boxed{230-x} \right)=29.9
\end{cases}
\\\\\\
0.09x+32.2-0.14x=29.9\implies -0.05x=-2.3\implies x=\cfrac{-2.3}{-0.05}
\\\\\\
x=46$

how many milliliters will it be for the second brand? well, y = 230 - x.

3 0

2 years ago

Anyone really good at math i have some questions.....PLEASE!!

Hunter-Best [27]

Answer:

I can help you!

Step-by-step explanation:

What do you need help with?

3 0

2 years ago