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Helga [31]
3 years ago
11

5x -6y=-32

Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0
So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)
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Someone please help me!
Vaselesa [24]
Look at 3 on Variable B's axis, then go to the right until you reach the line.

After you reach the line, go all the way down and see what number you get to on Variable A's axis. You get 8, so that is your answer.
7 0
3 years ago
A credit card company decides to study the frequency with which its cardholders charge for items from a certain change of retail
gregori [183]

Answer:

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 25 charged purchases and a standard distribution of 2

This means that \mu = 25, \sigma = 2

Proportion above 27

1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27 - 25}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?

0.1587*100% = 15.87%

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

6 0
3 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2
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[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]
\\\\\\
2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)
\\\\\\
\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}
\\\\\\
\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}
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\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}
\\\\\\
\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
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Zolol [24]

Answer:

\frac{-2}{x+1}

Step-by-step explanation:

x^3-2x+3-\frac{2}{x+1}

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5 0
3 years ago
A) x+(3x÷2y)<br>b) (b⁹)²×b⁵÷b¹¹=<br>c) (4²)⁶×4⁷÷4¹⁶=​
monitta

Answer:

a) x+3x/2y or (3x+2xy)/2y

b) b^12

c) 4^3 or 64

Step-by-step explanation:

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3 years ago
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