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3 years ago

Find the value of x in the triangle shown below.

Mathematics

2 answers:

Alinara [238K]3 years ago

6 0

9^2 = 8^2 + x^2
81 = 64 + x^2
x^2= 17
D

nekit [7.7K]3 years ago

5 0

Answer:

√17 = x

Step-by-step explanation:

The square value of hypotenus is equal to sum of other two side lenght's square value

9^ = x^+8^2

81 = x^2 + 64 subtract 64 from both sides

17 = x^2

√17 = x

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Step-by-step explanation:

(Refer to picture)

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

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