So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
<ERROR>--------------------------------------------------
Step-by-step explanation:
<ERROR>---------------------
-----------------------
-----
--
------
The length of the first piece is 4 the second piece is 8 and the third piece is 27. Your Welcome
Answer:
1.5 yards
Step-by-step explanation:
5 is half of 10
half of 3 is 1.5
I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!
Definition of eo-primes or relatively primes: Two numbers are said to be co-prime or relatively prime If their HCF IS 1 Hence to prove 847 and 2160 as co-prime numbers we will find their HCF and which should be 1
New steps to find HCF will be as under
2160 = 847 x 2+ 466
847 = 466 ×1 +381
466 = 381 x 1 + 85
381 =85 x 4+ 41
85 =41 x 2+3
41 =3 x 13+ 2
3 =2 x 1+1
2 =1 x 2+0
Therefore, the HCF=1 Hence, the numbers are co-primes (relatively prime).
