Answer:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
Step-by-step explanation:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
F(10) = (10)^2 + 1
= 100 + 1
= 101
Answer: integer's are whole numbers so a fraction,decimal and negitive numbers aren't integer's
Step-by-step explanation:
key words:
D=Diameter
R=Radius
D= 2r=2x1=2inches
so the diameter of the circle is 2 inches
hope this helps!
Simple....
you have:
![3x= \sqrt{12-12x}](https://tex.z-dn.net/?f=3x%3D%20%5Csqrt%7B12-12x%7D%20)
So...first you know you're trying to find x..
But, you have a square root on one side...to remove this you'd have to square both sides--->>>
![(3x)^{2} = \sqrt{12-12x} ^{2}](https://tex.z-dn.net/?f=%283x%29%5E%7B2%7D%20%3D%20%5Csqrt%7B12-12x%7D%20%20%5E%7B2%7D%20)
Leaving you with....
![9x^{2} =12-12x](https://tex.z-dn.net/?f=%209x%5E%7B2%7D%20%3D12-12x)
Move the terms over and set it equal to
zero.
-->>
![9x^{2}+12x-12=0](https://tex.z-dn.net/?f=%209x%5E%7B2%7D%2B12x-12%3D0%20)
Factor out a 3...
![3( 3x^{2} +4x-4=0)](https://tex.z-dn.net/?f=3%28%203x%5E%7B2%7D%20%2B4x-4%3D0%29)
What multiplies to -12 and adds to 4?
6*-2=-12
6+-2=4
Leaving you with...
![3(3x-2)(x+2)=0](https://tex.z-dn.net/?f=3%283x-2%29%28x%2B2%29%3D0)
Remember you're solving for 0....
3x-2=0
3x-2=0
+2 +2
3x=2
![\frac{3x}{3} = \frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7B3%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%20)
x=![\frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20)
Then-->>
x+2=0
x+2=0
-2 -2
x=-2
Thus, your answer.