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JulijaS [17]
2 years ago
13

Simplify this e5 x e4​

Mathematics
1 answer:
Gre4nikov [31]2 years ago
7 0

Answer:

hope it will help you

Step-by-step explanation:

follow me and like it.

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7/18 is closes to?<br><br>1/2<br><br>0<br><br>1
Anika [276]

Answer:

1/2

Step-by-step explanation:

Just divide 7 by 18.

7/18 = 0.38888888889

6 0
3 years ago
Solve the system using substitution.<br> y - 3x = 1<br> 2y - x = 12<br> ([?], [])
anyanavicka [17]

Answer:

(2, 5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y - 3x = 1

2y - x = 12

<u>Step 2: Rewrite Systems</u>

y - 3x = 1

  1. Add 3x on both sides:                    y = 3x + 1

<u>Step 3: Redefine Systems</u>

y = 3x + 1

2y - x = 12

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2(3x + 1) - x = 12
  2. Distribute 2:                         6x + 2 - x = 12
  3. Combine like terms:           5x + 2 = 12
  4. Isolate <em>x</em> term:                     5x = 10
  5. Isolate <em>x</em>:                              x = 2

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    2y - x = 12
  2. Substitute in <em>x</em>:                       2y - 2 = 12
  3. Isolate <em>y </em>term:                        2y = 10
  4. Isolate <em>y</em>:                                 y = 5
4 0
2 years ago
1-m<br> ___ =2/3 HELP PLEASE<br> 1+m
marusya05 [52]

Domain:\\\\1+m\neq0\to m\neq-1\\\\\dfrac{1-m}{1+m}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\3(1-m)=2(1+m)\qquad\text{use distributive property}\\\\(3)(1)+(3)(-m)=(2)(1)+(2)(m)\\\\3-3m=2+2m\qquad\text{subtract 3 from both sides}\\\\-3m=-1+2m\qquad\text{subtract 2m from both sides}\\\\-5m=-1\qquad\text{divide both sides by (-5)}\\\\m=\dfrac{1}{5}\neq-1\\\\Answer:\ \boxed{m=\dfrac{1}{5}}

7 0
3 years ago
1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
PLZ HELP NEED ANSWER QUICK
Elena L [17]
87+87+81+86+89+83+89= 602. Divided by 7 because that’s how many numbers there were is 86 and that is your mean/average.
7 0
3 years ago
Read 2 more answers
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