2 years ago

Simplify this e5 x e4

1 answer:

7 0

Answer:

hope it will help you

Step-by-step explanation:

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Aneli [31]

Explanation is in the file

tinyurl.com/wpazsebu

7 0

2 years ago

Softa [21]

Answer:

cool

Step-by-step explanation:

4 0

2 years ago

anyanavicka [17]

Factorizing the denominator gives

$\dfrac{x^4}{(x^3+x)(x^2-x+7)} = \dfrac{x^4}{x(x^2+1)(x^2-x+7)} = \dfrac{x^3}{(x^2+1)(x^2-x+7)}$

Then the partial fraction decomposition would take the form

$\dfrac{x^4}{(x^3+x)(x^2-x+7)} = \dfrac{a_0x + b_0}{x^2+1} + \dfrac{a_1x + b_1}{x^2-x+7}$

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2 years ago

ladessa [460]

Wouldnt the domain be x with the equal cross thingy 3

4 0

2 years ago

Jlenok [28]

2(x-3)=2x-6 This is distributive property.

2(x-3)= 2x - 2*3 = 2x-6

7 0

2 years ago

Simplify this e5 x e4​