Suppose JJ = Jhalil , J = Joman
1 - JJ 860 J620
2 - JJ 870 J 670
3- JJ880 J 720
4- JJ890 J 770
5- JJ900 J 820
6- JJ910 J 870
7- JJ920 J 920 - Catched up
8- JJ 930 J 970
9- JJ940 J 1020
10- JJ 950 J 1070
11- JJ960 J 1120
12- JJ 970 J 1170
so a - week 7
b- Joman
Answer:
Look below
Step-by-step explanation:
Part A: Equation would be in the y=mx+b format. m, or the slope, would be the cost that varies depending on the number of things that happen so m=3.25. b would be the fix cost so it is 15 so the equation ends up being y=$3.25x + $15.
Part B: Initial value is 15 since it is the fix cost, and 3.25 is the rate of change since it added as the number of rides increase.
Part 3: To solve this you substitute 7 into x so y=$3.25(7) + $15 = $37.75
I hope this explains it well.
Answer:
Total number of students in the college = 200 student
Step-by-step explanation:
Given:
Number of student make dean's list = 67 student
Percentage of student make dean's list = 33.5% of all student
Find:
Total number of students in the college
Computation:
Total number of students in the college = Number of student make dean's list / Percentage of student make dean's list
Total number of students in the college = 67 / 33.5%
Total number of students in the college = 67 / 0.335
Total number of students in the college = 200 student
I am sorry but I cannot see the picture properly, can you add another photo? Sorry for the inconvenience.
Answer:
Just to recap, an equation has no solution when it results in an incorrect "equation".
For example:
Equation: x+3 = x+4
Subtract x: 3 = 4???
But clearly, 3 is not equal to 4, so this equation has NO SOLUTION.
Now onto our problem:
13y+2-2y = 10y+3-y
11y+2 = 9y+3
2y=1
y=1/2
9(3y+7)-2 = 3(-9y+9)
27y+61 = -27y+27
54y = -34
y = -34/54
32.1y+3.1+2.4y-8.2=34.5y-5.1
34.5-5.1=34.5y-5.1
5.1=5.1
infinite solutions
5(2.2y+3.4) = 5(y-2)+6y
11y+17 = 11y-10
17 = -10??
That's not true, so the option "5(2.2y+3.4) = 5(y-2)+6y" has no solution.
Let me know if this helps
