There are 36 different possibilities for his lunch.
We can use the fundamental counting principal to solve this problem. We simply need to find the number of options for each part of the meal and multiply them.
Sandwich = 3
Snack = 3
Dessert = 2
Drink = 2
3 x 3 x 2 x 2 = 36
Answer:
x+4
x+1-2=x-1
Step-by-step explanation:
x+4/x-1=11/16 x should be different than 1 cz 1-1=0
16(x+4)=11(x-1)
16x+64=11x-11
16x-11x=-11-64
5x=-75
x=-15
-4.50 is closer to 0 so no
Answer:
The answer is that x = 6 and y = -6
Step-by-step explanation:
In order to find these values, we can use elimination. To do so, we multiply the first equation by 2 and then add the equations together.
4x + 8y = -24
-4x - 2y = -12
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6y = -36
y = -6
Now that we have this value, we can plug the value into one of the originals and find x.
2x + 4y = -12
2x + 4(-6) = -12
2x - 24 = -12
2x = 12
x = 6
