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Black_prince [1.1K]
3 years ago
12

Solve the equation below: 11(x+10)=132

Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

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Find the range of ƒ(x) = 3g – 5 for the domain {–1.5, 2, 4}
timofeeve [1]
-1.5 ------ f(x) = 3(-1.5) - 5
= -4.5 -5
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2 -------- f(x) = 3(2) - 5
= 6 -5
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4 -------- f(x) = 3(4) - 5
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6 0
3 years ago
If 6xa=54 and b-a=14 what is axb
bagirrra123 [75]
6a=54 so a=54/6, a=9

b-a=14, and using a found above...

b-9=14

b=23,  so a=9 and b=23 so

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6 0
3 years ago
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the vertex of this parabola is at (5,5). when the x-value is 6, the y-value is -1. what is the coefficient of the squared in the
zlopas [31]

Answer: OPTION D.

Step-by-step explanation:

The vertex form of a quadratic function is:

y= a(x - h)^2 + k

Where (h, k) is the vertex of the parabola and "a" is the coefficient of the squared in the parabola's equation.

We know that the vertex of this parabola is at (5,5) and we also know that when the x-value is 6, the y-value is -1.

Then  we can substitute values into  f (x) = a(x - h)^2 + k and solve for "a". This is:

-1= a(6- 5)^2 + 5\\\\-1=a+5\\\\-1-5=a\\\\a=-6

7 0
4 years ago
I’ll 40 points for these answers, thank you
attashe74 [19]
1. 24%
2. 13%
3. 60%


1. Since 6/25 is .24, 24% of the class was absent
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3. He ran 3 of the 5 miles, so 3/5 = 0.6.. meaning 60%. The time doesn’t matter
3 0
3 years ago
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Help me please please help with is!
frozen [14]
The answer for the question is 21
7 0
3 years ago
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