All categories

3 years ago

Help meh with this lol

Mathematics

2 answers:

lora16 [44]3 years ago

4 0

D is the answer because integers are negative numbers

egoroff_w [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Integers: a WHOLE number that can be positive, negative or zero

-22 is a negative whole number

Rational number: Any number that can be written as a fraction with integers.

-22/1 can be the fraction

You might be interested in

How do I turn 279x21 into a distributive property

Vilka [71]

(200plus79)x(20plus 1)
i am pretty sure

6 0

3 years ago

Write the equation of the parabola that has the vertex at point (2,7) and passes through

Anton [14]

Answer:

$f(x) = \frac{4}{3} (x - 2) ^{2} + 7$

Step-by-step explanation:

the answer is :- .

$f(x) = \frac{4}{3} (x - 2) ^{2} + 7$

6 0

2 years ago

Point F is at (0, -10) and point H is at (-6, 5). Find the coordinates of point G on line segment FH such that the ratio of FG t

Tanya [424]

Answer:

G(x,y)=(-4,0)

Step-by-step explanation:

We use the section formula:

$(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)$

Given:

$F(x_1,y_1)=(0, -10)\\H(x_2,y_2)=(-6, 5)\\FG:GH=m:n=2:1$

We substitute the values to get:

$G(x,y)=\left(\dfrac{2*-6+1*0}{2+1}, \dfrac{2*5+1*-10}{2+1}\right)\\=\left(\dfrac{-12}{3}, \dfrac{10-10}{3}\right)\\=\left(\dfrac{-12}{3}, \dfrac{0}{3}\right)\\\\G(x,y)=(-4,0)$

5 0

3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

7 0

3 years ago

I need help that is simple enough explnation

velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0

2 years ago