My boiii, tiger algebra helped me out a little on this one, I got 7c * sqrt(5)
<em><u>Question:</u></em>
Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?
<em><u>Answer:</u></em>
There will be $ 5920 in account after 15 years
<em><u>Solution:</u></em>
<em><u>The simple interest is given by formula:</u></em>

Where,
p is the principal
n is number of years
r is rate of interest
From given,
p = 3700
r = 4 %
t = 15 years
Therefore,

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>
Total money = principal + simple interest
Total money = 3700 + 2220
Total money = 5920
Thus there will be $ 5920 in account after 15 years
Answer:
711.11
Step-by-step explanation:
<h3>Method 1 </h3>
If 777 is decreased by 12%. the number would now be (100% - 12%) 88% of what it was originally
0.88 x 777 = 683.76
683.76 is increased by 4%. 683.76 would now be (100 + 4%) 104% of what it originally was
683.76 x 1.04 = 711.11
<h3>Method 2 </h3>
12% x 777 =
0.12 x 777 = 93.24
777 - 93.24 = 683.76
4% x 683.76 = 27.3504
683.76 + 27.3504 = 711.11
Answer: q(x) = 0.005(x - 40)² + 70
<u>Step-by-step explanation:</u>
f(x) = a(x - h)² + k <em>where a is the vertical stretch and (h, k) is the vertex.</em>
Which coordinate shifts the graph up?<em> The y-coordinate for the vertex is k.</em>
p(x) = 0.005(x - 40)² + 60
q(x) = 0.005(x - 40)² + 60 <u>+ 10</u>
= 0.005(x - 40)² + 70