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Brilliant_brown [7]
3 years ago
14

Make the most childish answer possible and ill give you brainliest

Mathematics
2 answers:
astra-53 [7]3 years ago
5 0

Answer and Step-by-step explanation:

         

Find [x]:  <--------------- (Childish Answer)

                                |

                                |

4 + y = 3x - 5            |

                                |

                                |

----------------------------^

^---------------

I found x!! ^

#teamtrees #WAP (Water And Plant)

Whitepunk [10]3 years ago
4 0

Answer:

yo mama

Step-by-step explanation:

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I think the correct answer is linear
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Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do
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Answer:

The population of bacteria can be expressed as a function of number of days.

Population = \[5*2^{n-1}\] where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day=\[5 * 2^{0} = 5\]

Number of bacteria on the second day = \[5 * 2^{1} = 10\]

Number of bacteria on the third day = \[5*2^{2} = 20\]

Number of bacteria on the fourth day = \[5*2^{3} = 40\]

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as \[5*2^{n-1}\] where n is the number of days since the beginning.

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3 years ago
Which fraction is bigger 7/8 or 14/15 using lcm
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3 years ago
What is mine times nine
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8 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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